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lief-project-LIEF/api/python/MachO/objects/pySubFramework.cpp
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Romain Thomas 77328b0071 Bump year
2022-02-08 21:16:25 +01:00

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/* Copyright 2017 - 2022 R. Thomas
* Copyright 2017 - 2022 Quarkslab
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
#include <algorithm>
#include <string>
#include <sstream>
#include "LIEF/MachO/hash.hpp"
#include "LIEF/MachO/SubFramework.hpp"
#include "pyMachO.hpp"
namespace LIEF {
namespace MachO {
template<class T>
using getter_t = T (SubFramework::*)(void) const;
template<class T>
using setter_t = void (SubFramework::*)(T);
template<>
void create<SubFramework>(py::module& m) {
py::class_<SubFramework, LoadCommand>(m, "SubFramework",
R"delim(
Class that represents the SubFramework command.
Accodring to the Mach-O ``loader.h`` documentation:
> A dynamically linked shared library may be a subframework of an umbrella
> framework. If so it will be linked with "-umbrella umbrella_name" where
> Where "umbrella_name" is the name of the umbrella framework. A subframework
> can only be linked against by its umbrella framework or other subframeworks
> that are part of the same umbrella framework. Otherwise the static link
> editor produces an error and states to link against the umbrella framework.
> The name of the umbrella framework for subframeworks is recorded in the
> following structure.
)delim")
.def_property("umbrella",
static_cast<getter_t<const std::string&>>(&SubFramework::umbrella),
static_cast<setter_t<const std::string&>>(&SubFramework::umbrella),
"Name of the umbrella framework")
.def("__eq__", &SubFramework::operator==)
.def("__ne__", &SubFramework::operator!=)
.def("__hash__",
[] (const SubFramework& func) {
return Hash::hash(func);
})
.def("__str__",
[] (const SubFramework& func)
{
std::ostringstream stream;
stream << func;
std::string str = stream.str();
return str;
});
}
}
}