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lief-project-LIEF/api/python/src/MachO/objects/pySubFramework.cpp
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2024-05-09 06:02:00 +02:00

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/* Copyright 2017 - 2024 R. Thomas
* Copyright 2017 - 2024 Quarkslab
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
#include <string>
#include <sstream>
#include <nanobind/stl/string.h>
#include "LIEF/MachO/SubFramework.hpp"
#include "MachO/pyMachO.hpp"
namespace LIEF::MachO::py {
template<>
void create<SubFramework>(nb::module_& m) {
nb::class_<SubFramework, LoadCommand>(m, "SubFramework",
R"delim(
Class that represents the SubFramework command.
Accodring to the Mach-O ``loader.h`` documentation:
> A dynamically linked shared library may be a subframework of an umbrella
> framework. If so it will be linked with "-umbrella umbrella_name" where
> Where "umbrella_name" is the name of the umbrella framework. A subframework
> can only be linked against by its umbrella framework or other subframeworks
> that are part of the same umbrella framework. Otherwise the static link
> editor produces an error and states to link against the umbrella framework.
> The name of the umbrella framework for subframeworks is recorded in the
> following structure.
)delim"_doc)
.def_prop_rw("umbrella",
nb::overload_cast<>(&SubFramework::umbrella, nb::const_),
nb::overload_cast<std::string>(&SubFramework::umbrella),
"Name of the umbrella framework"_doc)
LIEF_DEFAULT_STR(SubFramework);
}
}