Files
James Gross 80de840881 Even More Syntax Cleanup (#293)
A lot of cleanup things in prep for a python 3 transition. Getting rid of the old exception syntax, converting prints over to logging, cutting random scraps of code to be proper unit tests,  cut away some older bits of code, etc.

This still works in python2. It's just a lot of tidying up. There are no major functionality changes.
2020-09-08 13:00:06 -04:00

234 lines
6.0 KiB
Python

'''
Paths are enumerated threads through a particular graph. They
are implemented as an optimized hierarchical graph using python
primitives to save memory and processing time...
Each "leaf" node may be tracked back for it's entire path by
tracking back to parents.
'''
def newPathNode(parent=None, **kwargs):
'''
Create a new path node with the given properties
'''
ret = (parent, [], kwargs)
if parent is not None:
parent[1].append(ret)
return ret
def getNodeParent(pnode):
return pnode[0]
def delPathNode(pnode):
'''
Prune (remove) this node from the parent...
'''
p = getNodeParent(pnode)
if p is not None:
p[1].remove(pnode)
def getNodeIndex(pnode):
p = getNodeParent(pnode)
if p is not None:
return p[1].index(pnode)
return None
def getNodeKids(pnode):
'''
Return the list of children nodes for the specified
node.
Example: for knode in getNodeKids(pnode):
'''
return pnode[1]
def getRootNode(pnode):
'''
Get the root node for the path tree which contains
pnode.
Example: root = getRootNode(branchnode)
'''
ret = pnode
while pnode[0] is not None:
pnode = pnode[0]
return pnode
def getLeafNodes(pnode):
'''
Get all the leaf nodes for the path tree which contains
the pnode.
Example: for leaf in getLeafNodes(root):
'''
root = getRootNode(pnode)
ret = []
todo = [root, ]
while len(todo):
x = todo.pop()
if len(x[1]) == 0:
ret.append(x)
continue
for n in x[1]:
todo.append(n)
return ret
def getPathToNode(pnode):
'''
Return a list of the path nodes which lead from the
root node to the specified path node.
'''
path = []
while pnode is not None:
path.append(pnode)
pnode = pnode[0]
path.reverse()
return path
def getAllPaths(pnode):
'''
Get a list of lists which has each path flattened out.
Example: for path in getAllPaths(pnode):
for node in path:
doStuff()
'''
leafs = getLeafNodes(pnode)
paths = []
for leaf in leafs:
path = getPathToNode(leaf)
paths.append(path)
return paths
def getNodeProp(pnode, key, default=None):
'''
Get a property from the given node, returning
default in the case that the specified property is
not present.
Example:
name = getNodeProp(pnode, 'name', 'Unknown')
'''
return pnode[2].get(key, default)
def getPathProp(pnode, key, default=None):
'''
Retrieve the specified property by walking the give
path backward until the property is found. Returns
the specified default if the specified key is not found
as a property of any node in the given path.
Example:
name = getPathProp(pnode, 'name', 'Unknown')
'''
parent = pnode
while parent is not None:
parent, kids, props = parent
x = props.get(key)
if x is not None:
return x
return default
def setNodeProp(pnode, key, value):
'''
Set a spcified property on the given path node.
Example:
setNodeProp(pnode, 'name', 'woot')
'''
pnode[2][key] = value
def isPathLoop(pnode, key, value):
'''
Assuming you have some identifier property (such as graph node id)
being set on the path nodes, you may use this API to determine if
the current path has a node with the specified key/value property.
Example:
if searchPathLoop(pnode, 'nid', 5):
continue
'''
parent = pnode
while parent is not None:
parent, kids, props = parent
if props.get(key) == value:
return True
return False
def getPathLoopCount(pnode, key, value):
'''
Assuming that the key is unique, walk the current path and see how
many times "key" has the specified value. This will be how many instances
of a loop have been encountered.
'''
count = 0
parent = pnode
while parent is not None:
parent, kids, props = parent
if props.get(key) == value:
count += 1
return count
def trimPath(pnode):
'''
Doing analysis on a path tree can be very memory consuming. If an analysis tool is
powering through bajillions of nodes, the tree can consume all RAM. However,
the analysis may be doable with some selective trimming of the path tree.
Only trim when you are done with a path node, and make sure your algorithm uses
newPathNode on all "children" before traversing into one of them.
trimPath() will remove pnode from it's parent node, then check if the parent node
has any other children nodes, and recursively remove path links to all unnecessary
path nodes leading up to pnode.
caveat: if you are not calling newPathNode (which adds a reference from it's parent)
on all child nodes before traversing into any of them, it is possible that the
current node could be trimmed because it looks like it doesn't have any children.
'''
while True:
p = getNodeParent(pnode)
# if we don't have a parent, we're done
if p is None:
break
# remove our burden from our parent
if pnode in p[1]:
p[1].remove(pnode)
# if our parent still has kids living at home, we're done
if len(p[1]):
break
# time to kill our parent
pnode = p
def reprPath(node, startFromRoot=True):
r = ''
if startFromRoot:
node = getRootNode(node)
snid = getNodeProp(node, 'nid')
todo = [(snid, node, 1)]
r += hex(snid)
r += '\n'
while len(todo):
nid, pnode, indent = todo.pop()
for tpnode in pnode[1]:
tnid = getNodeProp(tpnode, 'nid')
outstr = " |"*indent + "--" + hex(tnid)
if tnid == snid:
outstr += " <<<<-- our node!"
r += outstr
r += '\n'
todo.append((tnid, tpnode, indent + 1))
return r